What are the solutions to the equation -5x^2+7x-1=0 ?

The solutions to the equation -5x^2+7x-1=0 are x=(7-sqrt(29))/(10),x=(7+sqrt(29))/(10)

Find the zeros of -5x^2+7x-1=0

The zeros of -5x^2+7x-1=0 are x=(7-sqrt(29))/(10),x=(7+sqrt(29))/(10)

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- 5 x^{2} + 7 x - 1 = 0

x = \frac{7 - 29}{10}, x = \frac{7 + 29}{10}

Decimal Notation

x = 0.16148 \dots, x = 1.23851 \dots

Solution steps

- 5 x^{2} + 7 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 ( - 5 ) ( - 1 )}{2 ( - 5 )}

7^{2} - 4 (- 5) (- 1) = 29

x_{1, 2} = \frac{- 7 \pm 29}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 7 + 29}{2 ( - 5 )}, x_{2} = \frac{- 7 - 29}{2 ( - 5 )}

x = \frac{- 7 + 29}{2 ( - 5 )} : \frac{7 - 29}{10}

x = \frac{- 7 - 29}{2 ( - 5 )} : \frac{7 + 29}{10}

The solutions to the quadratic equation are:

x = \frac{7 - 29}{10}, x = \frac{7 + 29}{10}

- x^{2} + 12 x - 6 = 0

x^{2} - 54 = - 5 x^{2}

5 x^{2} - 12 = 113

5 x^{2} + 11 x = - 2

y, y^{2} = x (4 - x)^{2}

What are the solutions to the equation -5x^2+7x-1=0 ?
The solutions to the equation -5x^2+7x-1=0 are x=(7-sqrt(29))/(10),x=(7+sqrt(29))/(10)
Find the zeros of -5x^2+7x-1=0
The zeros of -5x^2+7x-1=0 are x=(7-sqrt(29))/(10),x=(7+sqrt(29))/(10)