What are the solutions to the equation solvefor y,y^2=x(4-x)^2 ?

The solutions to the equation solvefor y,y^2=x(4-x)^2 are y=(4-x)sqrt(x),y=-(4-x)sqrt(x)

Find the zeros of solvefor y,y^2=x(4-x)^2

The zeros of solvefor y,y^2=x(4-x)^2 are y=(4-x)sqrt(x),y=-(4-x)sqrt(x)

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solve for

y, y^{2} = x (4 - x)^{2}

y = (4 - x) x, y = - (4 - x) x

Solution steps

y^{2} = x (4 - x)^{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = x (4 - x)^{2}, y = - x (4 - x)^{2}

Simplify

x (4 - x)^{2} : (4 - x) x

Simplify

- x (4 - x)^{2} : - (4 - x) x

y = (4 - x) x, y = - (4 - x) x

x^{2} - 20 x + 20 = 0

x, x^{2} y = 10

\frac{x ^{2} + 2 x}{7} = 9

18 x^{2} + 36 x = 0

5 x^{2} - 22 x = - 8

What are the solutions to the equation solvefor y,y^2=x(4-x)^2 ?
The solutions to the equation solvefor y,y^2=x(4-x)^2 are y=(4-x)sqrt(x),y=-(4-x)sqrt(x)
Find the zeros of solvefor y,y^2=x(4-x)^2
The zeros of solvefor y,y^2=x(4-x)^2 are y=(4-x)sqrt(x),y=-(4-x)sqrt(x)