What are the solutions to the equation x^2-20x+20=0 ?

The solutions to the equation x^2-20x+20=0 are x=2(5+2sqrt(5)),x=2(5-2sqrt(5))

Find the zeros of x^2-20x+20=0

The zeros of x^2-20x+20=0 are x=2(5+2sqrt(5)),x=2(5-2sqrt(5))

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x^{2} - 20 x + 20 = 0

x = 2 (5 + 25), x = 2 (5 - 25)

Decimal

x = 18.94427 \dots, x = 1.05572 \dots

Solution steps

x^{2} - 20 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

(- 20)^{2} - 4 \cdot 1 \cdot 20 = 85

x_{1, 2} = \frac{- ( - 20 ) \pm 8 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 8 5}{2 \cdot 1}, x_{2} = \frac{- ( - 20 ) - 8 5}{2 \cdot 1}

x = \frac{- ( - 20 ) + 8 5}{2 \cdot 1} : 2 (5 + 25)

x = \frac{- ( - 20 ) - 8 5}{2 \cdot 1} : 2 (5 - 25)

The solutions to the quadratic equation are:

x = 2 (5 + 25), x = 2 (5 - 25)

x, x^{2} y = 10

\frac{x ^{2} + 2 x}{7} = 9

18 x^{2} + 36 x = 0

5 x^{2} - 22 x = - 8

u^{2} + u = 2

What are the solutions to the equation x^2-20x+20=0 ?
The solutions to the equation x^2-20x+20=0 are x=2(5+2sqrt(5)),x=2(5-2sqrt(5))
Find the zeros of x^2-20x+20=0
The zeros of x^2-20x+20=0 are x=2(5+2sqrt(5)),x=2(5-2sqrt(5))