What are the solutions to the equation u^2+u=2 ?

The solutions to the equation u^2+u=2 are u=1,u=-2

Find the zeros of u^2+u=2

The zeros of u^2+u=2 are u=1,u=-2

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u^{2} + u = 2

u = 1, u = - 2

Solution steps

u^{2} + u = 2

Move

2

to the left side

u^{2} + u - 2 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 2) = 3

u_{1, 2} = \frac{- 1 \pm 3}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- 1 + 3}{2 \cdot 1}, u_{2} = \frac{- 1 - 3}{2 \cdot 1}

u = \frac{- 1 + 3}{2 \cdot 1} : 1

u = \frac{- 1 - 3}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

u = 1, u = - 2

x, x^{2} + k x + 6 = 0

5 x^{2} + x - 10 = 0

\frac{x ^{2}}{4} + \frac{2 x}{3} = 0

11 x^{2} - 13 x = 0

8 + 2 x - 3 x^{2} = 0

What are the solutions to the equation u^2+u=2 ?
The solutions to the equation u^2+u=2 are u=1,u=-2
Find the zeros of u^2+u=2
The zeros of u^2+u=2 are u=1,u=-2