What are the solutions to the equation 6x^2+5=30+2x^2 ?

The solutions to the equation 6x^2+5=30+2x^2 are x= 5/2 ,x=-5/2

Find the zeros of 6x^2+5=30+2x^2

The zeros of 6x^2+5=30+2x^2 are x= 5/2 ,x=-5/2

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6 x^{2} + 5 = 30 + 2 x^{2}

x = \frac{5}{2}, x = - \frac{5}{2}

Solution steps

6 x^{2} + 5 = 30 + 2 x^{2}

Move

5

to the right side

6 x^{2} = 2 x^{2} + 25

Move

2 x^{2}

to the left side

4 x^{2} = 25

Divide both sides by

4

x^{2} = \frac{25}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{25}{4}, x = - \frac{25}{4}

\frac{25}{4} = \frac{5}{2}

- \frac{25}{4} = - \frac{5}{2}

x = \frac{5}{2}, x = - \frac{5}{2}

x, y^{4} = x^{2} + 16

4 x^{2} - 32 x + 20 = 0

2 x^{2} + 16 x - 11

x^{2} + \frac{1}{4} = 1

2 x^{2} + 6 x + 3

What are the solutions to the equation 6x^2+5=30+2x^2 ?
The solutions to the equation 6x^2+5=30+2x^2 are x= 5/2 ,x=-5/2
Find the zeros of 6x^2+5=30+2x^2
The zeros of 6x^2+5=30+2x^2 are x= 5/2 ,x=-5/2