9x^2-48x+54=0

解答

9 x^{2} - 48 x + 54 = 0

x = \frac{8 + 10}{3}, x = \frac{8 - 10}{3}

求解步骤

9 x^{2} - 48 x + 54 = 0

使用求根公式求解

x_{1, 2} = \frac{- ( - 48 ) \pm ( - 48 ) ^{2} - 4 \cdot 9 \cdot 54}{2 \cdot 9}

(- 48)^{2} - 4 \cdot 9 \cdot 54 = 610

x_{1, 2} = \frac{- ( - 48 ) \pm 6 10}{2 \cdot 9}

将解分隔开

x_{1} = \frac{- ( - 48 ) + 6 10}{2 \cdot 9}, x_{2} = \frac{- ( - 48 ) - 6 10}{2 \cdot 9}

x = \frac{- ( - 48 ) + 6 10}{2 \cdot 9} : \frac{8 + 10}{3}

x = \frac{- ( - 48 ) - 6 10}{2 \cdot 9} : \frac{8 - 10}{3}

二次方程组的解是:

x = \frac{8 + 10}{3}, x = \frac{8 - 10}{3}

4.905 t^{2} - 90.27 t - 150 = 0

3 x^{2} + 30 x + 72 = 0

4 x^{2} + 43 x + 3 = 0

x, y = x^{2} + p x + q

x, f (a + 1) = 4 x^{2} - x + 5