What are the solutions to the equation 9x^2-48x+54=0 ?

The solutions to the equation 9x^2-48x+54=0 are x=(8+sqrt(10))/3 ,x=(8-sqrt(10))/3

Find the zeros of 9x^2-48x+54=0

The zeros of 9x^2-48x+54=0 are x=(8+sqrt(10))/3 ,x=(8-sqrt(10))/3

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9 x^{2} - 48 x + 54 = 0

x = \frac{8 + 10}{3}, x = \frac{8 - 10}{3}

Decimal Notation

x = 3.72075 \dots, x = 1.61257 \dots

Solution steps

9 x^{2} - 48 x + 54 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 48 ) \pm ( - 48 ) ^{2} - 4 \cdot 9 \cdot 54}{2 \cdot 9}

(- 48)^{2} - 4 \cdot 9 \cdot 54 = 610

x_{1, 2} = \frac{- ( - 48 ) \pm 6 10}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 48 ) + 6 10}{2 \cdot 9}, x_{2} = \frac{- ( - 48 ) - 6 10}{2 \cdot 9}

x = \frac{- ( - 48 ) + 6 10}{2 \cdot 9} : \frac{8 + 10}{3}

x = \frac{- ( - 48 ) - 6 10}{2 \cdot 9} : \frac{8 - 10}{3}

The solutions to the quadratic equation are:

x = \frac{8 + 10}{3}, x = \frac{8 - 10}{3}

4.905 t^{2} - 90.27 t - 150 = 0

3 x^{2} + 30 x + 72 = 0

4 x^{2} + 43 x + 3 = 0

x, y = x^{2} + p x + q

x, f (a + 1) = 4 x^{2} - x + 5

What are the solutions to the equation 9x^2-48x+54=0 ?
The solutions to the equation 9x^2-48x+54=0 are x=(8+sqrt(10))/3 ,x=(8-sqrt(10))/3
Find the zeros of 9x^2-48x+54=0
The zeros of 9x^2-48x+54=0 are x=(8+sqrt(10))/3 ,x=(8-sqrt(10))/3