What are the solutions to the equation 3x^2+30x+72=0 ?

The solutions to the equation 3x^2+30x+72=0 are x=-4,x=-6

Find the zeros of 3x^2+30x+72=0

The zeros of 3x^2+30x+72=0 are x=-4,x=-6

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3 x^{2} + 30 x + 72 = 0

x = - 4, x = - 6

Solution steps

3 x^{2} + 30 x + 72 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 30 \pm 3 0 ^{2} - 4 \cdot 3 \cdot 72}{2 \cdot 3}

3 0^{2} - 4 \cdot 3 \cdot 72 = 6

x_{1, 2} = \frac{- 30 \pm 6}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 30 + 6}{2 \cdot 3}, x_{2} = \frac{- 30 - 6}{2 \cdot 3}

x = \frac{- 30 + 6}{2 \cdot 3} : - 4

x = \frac{- 30 - 6}{2 \cdot 3} : - 6

The solutions to the quadratic equation are:

x = - 4, x = - 6

4 x^{2} + 43 x + 3 = 0

x, y = x^{2} + p x + q

x, f (a + 1) = 4 x^{2} - x + 5

(x - 5)^{2} + x (x + 3) = 25

5 x^{2} - 12 x - 8 = 0

What are the solutions to the equation 3x^2+30x+72=0 ?
The solutions to the equation 3x^2+30x+72=0 are x=-4,x=-6
Find the zeros of 3x^2+30x+72=0
The zeros of 3x^2+30x+72=0 are x=-4,x=-6