What are the solutions to the equation 5x^2-12x-8=0 ?

The solutions to the equation 5x^2-12x-8=0 are x=(2(3+sqrt(19)))/5 ,x=(2(3-sqrt(19)))/5

Find the zeros of 5x^2-12x-8=0

The zeros of 5x^2-12x-8=0 are x=(2(3+sqrt(19)))/5 ,x=(2(3-sqrt(19)))/5

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5 x^{2} - 12 x - 8 = 0

x = \frac{2 ( 3 + 19 )}{5}, x = \frac{2 ( 3 - 19 )}{5}

Decimal Notation

x = 2.94355 \dots, x = - 0.54355 \dots

Solution steps

5 x^{2} - 12 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 5 ( - 8 )}{2 \cdot 5}

(- 12)^{2} - 4 \cdot 5 (- 8) = 419

x_{1, 2} = \frac{- ( - 12 ) \pm 4 19}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 4 19}{2 \cdot 5}, x_{2} = \frac{- ( - 12 ) - 4 19}{2 \cdot 5}

x = \frac{- ( - 12 ) + 4 19}{2 \cdot 5} : \frac{2 ( 3 + 19 )}{5}

x = \frac{- ( - 12 ) - 4 19}{2 \cdot 5} : \frac{2 ( 3 - 19 )}{5}

The solutions to the quadratic equation are:

x = \frac{2 ( 3 + 19 )}{5}, x = \frac{2 ( 3 - 19 )}{5}

x^{2} - 3 = 4 x + 2

2 (x - 1)^{2} - 8 = 0

29 = x^{2} + 4

x, f = u_{1} (x^{2})

s^{2} + 4 s - 21 = 0

What are the solutions to the equation 5x^2-12x-8=0 ?
The solutions to the equation 5x^2-12x-8=0 are x=(2(3+sqrt(19)))/5 ,x=(2(3-sqrt(19)))/5
Find the zeros of 5x^2-12x-8=0
The zeros of 5x^2-12x-8=0 are x=(2(3+sqrt(19)))/5 ,x=(2(3-sqrt(19)))/5