What are the solutions to the equation 2(x-1)^2-8=0 ?

The solutions to the equation 2(x-1)^2-8=0 are x=3,x=-1

Find the zeros of 2(x-1)^2-8=0

The zeros of 2(x-1)^2-8=0 are x=3,x=-1

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2 (x - 1)^{2} - 8 = 0

x = 3, x = - 1

Solution steps

2 (x - 1)^{2} - 8 = 0

Move

8

to the right side

2 (x - 1)^{2} = 8

Divide both sides by

2

(x - 1)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 1 = 4 : x = 3

Solve

x - 1 = - 4 : x = - 1

The solutions to the quadratic equation are:

x = 3, x = - 1

29 = x^{2} + 4

x, f = u_{1} (x^{2})

s^{2} + 4 s - 21 = 0

0 = 75 + 28925 \cdot t - 5 \cdot t^{2}

4 n^{2} - 7 n - 85 = 7

What are the solutions to the equation 2(x-1)^2-8=0 ?
The solutions to the equation 2(x-1)^2-8=0 are x=3,x=-1
Find the zeros of 2(x-1)^2-8=0
The zeros of 2(x-1)^2-8=0 are x=3,x=-1