What are the solutions to the equation z^2+11z+16=0 ?

The solutions to the equation z^2+11z+16=0 are z=(-11+sqrt(57))/2 ,z=(-11-sqrt(57))/2

Find the zeros of z^2+11z+16=0

The zeros of z^2+11z+16=0 are z=(-11+sqrt(57))/2 ,z=(-11-sqrt(57))/2

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z^{2} + 11 z + 16 = 0

z = \frac{- 11 + 57}{2}, z = \frac{- 11 - 57}{2}

Decimal Notation

z = - 1.72508 \dots, z = - 9.27491 \dots

Solution steps

z^{2} + 11 z + 16 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

1 1^{2} - 4 \cdot 1 \cdot 16 = 57

z_{1, 2} = \frac{- 11 \pm 57}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- 11 + 57}{2 \cdot 1}, z_{2} = \frac{- 11 - 57}{2 \cdot 1}

z = \frac{- 11 + 57}{2 \cdot 1} : \frac{- 11 + 57}{2}

z = \frac{- 11 - 57}{2 \cdot 1} : \frac{- 11 - 57}{2}

The solutions to the quadratic equation are:

z = \frac{- 11 + 57}{2}, z = \frac{- 11 - 57}{2}

(x - \frac{1}{2})^{2} = 0

x^{2} + 3 k + 1 = (k + 2) x

x, (x^{5})^{2} = 7 y y^{5}

4 x^{2} - 8 x = 12

4 w^{2} + 19 w - 5 = 0

What are the solutions to the equation z^2+11z+16=0 ?
The solutions to the equation z^2+11z+16=0 are z=(-11+sqrt(57))/2 ,z=(-11-sqrt(57))/2
Find the zeros of z^2+11z+16=0
The zeros of z^2+11z+16=0 are z=(-11+sqrt(57))/2 ,z=(-11-sqrt(57))/2