What are the solutions to the equation 2c^2+3c+2=-10 ?

The solutions to the equation 2c^2+3c+2=-10 are c=-3/4+i(sqrt(87))/4 ,c=-3/4-i(sqrt(87))/4

Find the zeros of 2c^2+3c+2=-10

The zeros of 2c^2+3c+2=-10 are c=-3/4+i(sqrt(87))/4 ,c=-3/4-i(sqrt(87))/4

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2 c^{2} + 3 c + 2 = - 10

c = - \frac{3}{4} + i \frac{87}{4}, c = - \frac{3}{4} - i \frac{87}{4}

Solution steps

2 c^{2} + 3 c + 2 = - 10

Move

10

to the left side

2 c^{2} + 3 c + 12 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 2 \cdot 12}{2 \cdot 2}

Simplify

3^{2} - 4 \cdot 2 \cdot 12 : 87 i

c_{1, 2} = \frac{- 3 \pm 87 i}{2 \cdot 2}

Separate the solutions

c_{1} = \frac{- 3 + 87 i}{2 \cdot 2}, c_{2} = \frac{- 3 - 87 i}{2 \cdot 2}

c = \frac{- 3 + 87 i}{2 \cdot 2} : - \frac{3}{4} + i \frac{87}{4}

c = \frac{- 3 - 87 i}{2 \cdot 2} : - \frac{3}{4} - i \frac{87}{4}

The solutions to the quadratic equation are:

c = - \frac{3}{4} + i \frac{87}{4}, c = - \frac{3}{4} - i \frac{87}{4}

2 x^{2} - 16 x = - 24

4 w^{2} - 8 w - 5 = 0

3 x (x - 1) = 6

6 x^{2} - 24 = 30

2 x (x - 5) = x + 3

What are the solutions to the equation 2c^2+3c+2=-10 ?
The solutions to the equation 2c^2+3c+2=-10 are c=-3/4+i(sqrt(87))/4 ,c=-3/4-i(sqrt(87))/4
Find the zeros of 2c^2+3c+2=-10
The zeros of 2c^2+3c+2=-10 are c=-3/4+i(sqrt(87))/4 ,c=-3/4-i(sqrt(87))/4