What are the solutions to the equation 4w^2-8w-5=0 ?

The solutions to the equation 4w^2-8w-5=0 are w= 5/2 ,w=-1/2

Find the zeros of 4w^2-8w-5=0

The zeros of 4w^2-8w-5=0 are w= 5/2 ,w=-1/2

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4 w^{2} - 8 w - 5 = 0

w = \frac{5}{2}, w = - \frac{1}{2}

Decimal Notation

w = 2.5, w = - 0.5

Solution steps

4 w^{2} - 8 w - 5 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 4 ( - 5 )}{2 \cdot 4}

(- 8)^{2} - 4 \cdot 4 (- 5) = 12

w_{1, 2} = \frac{- ( - 8 ) \pm 12}{2 \cdot 4}

Separate the solutions

w_{1} = \frac{- ( - 8 ) + 12}{2 \cdot 4}, w_{2} = \frac{- ( - 8 ) - 12}{2 \cdot 4}

w = \frac{- ( - 8 ) + 12}{2 \cdot 4} : \frac{5}{2}

w = \frac{- ( - 8 ) - 12}{2 \cdot 4} : - \frac{1}{2}

The solutions to the quadratic equation are:

w = \frac{5}{2}, w = - \frac{1}{2}

3 x (x - 1) = 6

6 x^{2} - 24 = 30

2 x (x - 5) = x + 3

(a x + 7 b)^{2} - (b x + 7 a)^{2} = 0

- 9 v + 2 = v^{2} + 20

What are the solutions to the equation 4w^2-8w-5=0 ?
The solutions to the equation 4w^2-8w-5=0 are w= 5/2 ,w=-1/2
Find the zeros of 4w^2-8w-5=0
The zeros of 4w^2-8w-5=0 are w= 5/2 ,w=-1/2