What are the solutions to the equation (ax+7b)^2-(bx+7a)^2=0 ?

The solutions to the equation (ax+7b)^2-(bx+7a)^2=0 are x=-7,x=7;\quad a\ne-b,a\ne b

Find the zeros of (ax+7b)^2-(bx+7a)^2=0

The zeros of (ax+7b)^2-(bx+7a)^2=0 are x=-7,x=7;\quad a\ne-b,a\ne b

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(a x + 7 b)^{2} - (b x + 7 a)^{2} = 0

x = - 7, x = 7; a \neq = - b, a \neq = b

Solution steps

(a x + 7 b)^{2} - (b x + 7 a)^{2} = 0

Factor

(a x + 7 b)^{2} - (b x + 7 a)^{2} : (a x + 7 a + 7 b + b x) (a x - 7 a + 7 b - b x)

(a x + 7 a + 7 b + b x) (a x - 7 a + 7 b - b x) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

a x + 7 a + 7 b + b x = 0 or a x - 7 a + 7 b - b x = 0

Solve

a x + 7 a + 7 b + b x = 0 : x = - 7; a \neq = - b

Solve

a x - 7 a + 7 b - b x = 0 : x = 7; a \neq = b

The solutions to the quadratic equation are:

x = - 7, x = 7; a \neq = - b, a \neq = b

- 9 v + 2 = v^{2} + 20

(x - 1)^{2} - 24 = 0

n^{2} + 5 n - 14 = 0

(x - 2) (3 - 2 x) = 3

(2 y + 9)^{2} = 81

What are the solutions to the equation (ax+7b)^2-(bx+7a)^2=0 ?
The solutions to the equation (ax+7b)^2-(bx+7a)^2=0 are x=-7,x=7;\quad a\ne-b,a\ne b
Find the zeros of (ax+7b)^2-(bx+7a)^2=0
The zeros of (ax+7b)^2-(bx+7a)^2=0 are x=-7,x=7;\quad a\ne-b,a\ne b