What are the solutions to the equation -2x^2+3x+3=0 ?

The solutions to the equation -2x^2+3x+3=0 are x=-(-3+sqrt(33))/4 ,x=(3+sqrt(33))/4

Find the zeros of -2x^2+3x+3=0

The zeros of -2x^2+3x+3=0 are x=-(-3+sqrt(33))/4 ,x=(3+sqrt(33))/4

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- 2 x^{2} + 3 x + 3 = 0

x = - \frac{- 3 + 33}{4}, x = \frac{3 + 33}{4}

Solution steps

- 2 x^{2} + 3 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 2 ) \cdot 3}{2 ( - 2 )}

3^{2} - 4 (- 2) \cdot 3 = 33

x_{1, 2} = \frac{- 3 \pm 33}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 3 + 33}{2 ( - 2 )}, x_{2} = \frac{- 3 - 33}{2 ( - 2 )}

x = \frac{- 3 + 33}{2 ( - 2 )} : - \frac{- 3 + 33}{4}

x = \frac{- 3 - 33}{2 ( - 2 )} : \frac{3 + 33}{4}

The solutions to the quadratic equation are:

x = - \frac{- 3 + 33}{4}, x = \frac{3 + 33}{4}

5 (x + 3)^{2} = 2

x, y = 3 - x^{2}

V = π r^{2} h, r

8 x^{2} - 6 x + 3 = 0

2 a^{2} + 3 a - 5 = - 1

What are the solutions to the equation -2x^2+3x+3=0 ?
The solutions to the equation -2x^2+3x+3=0 are x=-(-3+sqrt(33))/4 ,x=(3+sqrt(33))/4
Find the zeros of -2x^2+3x+3=0
The zeros of -2x^2+3x+3=0 are x=-(-3+sqrt(33))/4 ,x=(3+sqrt(33))/4