What are the solutions to the equation 2x(x+3)=5 ?

The solutions to the equation 2x(x+3)=5 are x=(-3+sqrt(19))/2 ,x=-(3+sqrt(19))/2

Find the zeros of 2x(x+3)=5

The zeros of 2x(x+3)=5 are x=(-3+sqrt(19))/2 ,x=-(3+sqrt(19))/2

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2 x (x + 3) = 5

x = \frac{- 3 + 19}{2}, x = - \frac{3 + 19}{2}

Decimal Notation

x = 0.67944 \dots, x = - 3.67944 \dots

Solution steps

2 x (x + 3) = 5

Expand

2 x (x + 3) : 2 x^{2} + 6 x

2 x^{2} + 6 x = 5

Move

5

to the left side

2 x^{2} + 6 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 2 ( - 5 )}{2 \cdot 2}

6^{2} - 4 \cdot 2 (- 5) = 219

x_{1, 2} = \frac{- 6 \pm 2 19}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 6 + 2 19}{2 \cdot 2}, x_{2} = \frac{- 6 - 2 19}{2 \cdot 2}

x = \frac{- 6 + 2 19}{2 \cdot 2} : \frac{- 3 + 19}{2}

x = \frac{- 6 - 2 19}{2 \cdot 2} : - \frac{3 + 19}{2}

The solutions to the quadratic equation are:

x = \frac{- 3 + 19}{2}, x = - \frac{3 + 19}{2}

6 x^{2} = 7 - 11 x

(y + 5)^{2} - 25 = 0

(r + 7)^{2} + 9 = 0

9 y^{2} + 12 y = 0

3 x^{2} + 14 x = - 11

What are the solutions to the equation 2x(x+3)=5 ?
The solutions to the equation 2x(x+3)=5 are x=(-3+sqrt(19))/2 ,x=-(3+sqrt(19))/2
Find the zeros of 2x(x+3)=5
The zeros of 2x(x+3)=5 are x=(-3+sqrt(19))/2 ,x=-(3+sqrt(19))/2