What are the solutions to the equation 3x^2+14x=-11 ?

The solutions to the equation 3x^2+14x=-11 are x=-1,x=-11/3

Find the zeros of 3x^2+14x=-11

The zeros of 3x^2+14x=-11 are x=-1,x=-11/3

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3 x^{2} + 14 x = - 11

x = - 1, x = - \frac{11}{3}

Solution steps

3 x^{2} + 14 x = - 11

Move

11

to the left side

3 x^{2} + 14 x + 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 3 \cdot 11}{2 \cdot 3}

1 4^{2} - 4 \cdot 3 \cdot 11 = 8

x_{1, 2} = \frac{- 14 \pm 8}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 14 + 8}{2 \cdot 3}, x_{2} = \frac{- 14 - 8}{2 \cdot 3}

x = \frac{- 14 + 8}{2 \cdot 3} : - 1

x = \frac{- 14 - 8}{2 \cdot 3} : - \frac{11}{3}

The solutions to the quadratic equation are:

x = - 1, x = - \frac{11}{3}

(11 - x) (6 + x) = 2 (x - 2)^{2}

6 x^{2} - 29 x - 534 = 7 x

5 - (x + 3) = 4 x^{2}

u^{2} - 40 u + 400 = 16

q^{2} - 3 q - 11 = - 6 q

What are the solutions to the equation 3x^2+14x=-11 ?
The solutions to the equation 3x^2+14x=-11 are x=-1,x=-11/3
Find the zeros of 3x^2+14x=-11
The zeros of 3x^2+14x=-11 are x=-1,x=-11/3