What are the solutions to the equation 6x^2-29x-534=7x ?

The solutions to the equation 6x^2-29x-534=7x are x=3+7sqrt(2),x=3-7sqrt(2)

Find the zeros of 6x^2-29x-534=7x

The zeros of 6x^2-29x-534=7x are x=3+7sqrt(2),x=3-7sqrt(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

6 x^{2} - 29 x - 534 = 7 x

x = 3 + 72, x = 3 - 72

Decimal Notation

x = 12.89949 \dots, x = - 6.89949 \dots

Solution steps

6 x^{2} - 29 x - 534 = 7 x

Move

7 x

to the left side

6 x^{2} - 36 x - 534 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 36 ) \pm ( - 36 ) ^{2} - 4 \cdot 6 ( - 534 )}{2 \cdot 6}

(- 36)^{2} - 4 \cdot 6 (- 534) = 842

x_{1, 2} = \frac{- ( - 36 ) \pm 84 2}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 36 ) + 84 2}{2 \cdot 6}, x_{2} = \frac{- ( - 36 ) - 84 2}{2 \cdot 6}

x = \frac{- ( - 36 ) + 84 2}{2 \cdot 6} : 3 + 72

x = \frac{- ( - 36 ) - 84 2}{2 \cdot 6} : 3 - 72

The solutions to the quadratic equation are:

x = 3 + 72, x = 3 - 72

5 - (x + 3) = 4 x^{2}

u^{2} - 40 u + 400 = 16

q^{2} - 3 q - 11 = - 6 q

(36 - r)^{2} + (18 - r)^{2} = r^{2}

(62)^{2} = x^{2} + x^{2}

What are the solutions to the equation 6x^2-29x-534=7x ?
The solutions to the equation 6x^2-29x-534=7x are x=3+7sqrt(2),x=3-7sqrt(2)
Find the zeros of 6x^2-29x-534=7x
The zeros of 6x^2-29x-534=7x are x=3+7sqrt(2),x=3-7sqrt(2)