What are the solutions to the equation u^2-40u+400=16 ?

The solutions to the equation u^2-40u+400=16 are u=24,u=16

Find the zeros of u^2-40u+400=16

The zeros of u^2-40u+400=16 are u=24,u=16

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u^{2} - 40 u + 400 = 16

u = 24, u = 16

Solution steps

u^{2} - 40 u + 400 = 16

Move

16

to the left side

u^{2} - 40 u + 384 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 40 ) \pm ( - 40 ) ^{2} - 4 \cdot 1 \cdot 384}{2 \cdot 1}

(- 40)^{2} - 4 \cdot 1 \cdot 384 = 8

u_{1, 2} = \frac{- ( - 40 ) \pm 8}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- ( - 40 ) + 8}{2 \cdot 1}, u_{2} = \frac{- ( - 40 ) - 8}{2 \cdot 1}

u = \frac{- ( - 40 ) + 8}{2 \cdot 1} : 24

u = \frac{- ( - 40 ) - 8}{2 \cdot 1} : 16

The solutions to the quadratic equation are:

u = 24, u = 16

q^{2} - 3 q - 11 = - 6 q

(36 - r)^{2} + (18 - r)^{2} = r^{2}

(62)^{2} = x^{2} + x^{2}

15 + 7 k = 2 k^{2}

2 x^{2} + 12 x + 2 = 0

What are the solutions to the equation u^2-40u+400=16 ?
The solutions to the equation u^2-40u+400=16 are u=24,u=16
Find the zeros of u^2-40u+400=16
The zeros of u^2-40u+400=16 are u=24,u=16