What are the solutions to the equation 14x^2-4x=35x-10 ?

The solutions to the equation 14x^2-4x=35x-10 are x= 5/2 ,x= 2/7

Find the zeros of 14x^2-4x=35x-10

The zeros of 14x^2-4x=35x-10 are x= 5/2 ,x= 2/7

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14 x^{2} - 4 x = 35 x - 10

x = \frac{5}{2}, x = \frac{2}{7}

Decimal Notation

x = 2.5, x = 0.28571 \dots

Solution steps

14 x^{2} - 4 x = 35 x - 10

Move

10

to the left side

14 x^{2} - 4 x + 10 = 35 x

Move

35 x

to the left side

14 x^{2} - 39 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 39 ) \pm ( - 39 ) ^{2} - 4 \cdot 14 \cdot 10}{2 \cdot 14}

(- 39)^{2} - 4 \cdot 14 \cdot 10 = 31

x_{1, 2} = \frac{- ( - 39 ) \pm 31}{2 \cdot 14}

Separate the solutions

x_{1} = \frac{- ( - 39 ) + 31}{2 \cdot 14}, x_{2} = \frac{- ( - 39 ) - 31}{2 \cdot 14}

x = \frac{- ( - 39 ) + 31}{2 \cdot 14} : \frac{5}{2}

x = \frac{- ( - 39 ) - 31}{2 \cdot 14} : \frac{2}{7}

The solutions to the quadratic equation are:

x = \frac{5}{2}, x = \frac{2}{7}

n (n + 6) = 520

x^{2} = 255

(2 x - 1)^{2} + (3 x - 2)^{2} = 5

2 (x - 4)^{2} = 200

4 (x + 1)^{2} = (x - 2)^{2}

What are the solutions to the equation 14x^2-4x=35x-10 ?
The solutions to the equation 14x^2-4x=35x-10 are x= 5/2 ,x= 2/7
Find the zeros of 14x^2-4x=35x-10
The zeros of 14x^2-4x=35x-10 are x= 5/2 ,x= 2/7