What are the solutions to the equation 2x^2-5=8 ?

The solutions to the equation 2x^2-5=8 are x=sqrt(13/2),x=-sqrt(13/2)

Find the zeros of 2x^2-5=8

The zeros of 2x^2-5=8 are x=sqrt(13/2),x=-sqrt(13/2)

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2 x^{2} - 5 = 8

x = \frac{13}{2}, x = - \frac{13}{2}

Decimal Notation

x = 2.54950 \dots, x = - 2.54950 \dots

Solution steps

2 x^{2} - 5 = 8

Move

5

to the right side

2 x^{2} = 13

Divide both sides by

2

x^{2} = \frac{13}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{13}{2}, x = - \frac{13}{2}

3 x^{2} + 6 x - 18 = 0

3 x^{2} - 2 = 2 x - 1

(x - 4)^{2} = (3 - x) (1 + 2 x)

t, e = \frac{1}{2} a t^{2}

9 x^{2} - 73 x + 73 = 0

What are the solutions to the equation 2x^2-5=8 ?
The solutions to the equation 2x^2-5=8 are x=sqrt(13/2),x=-sqrt(13/2)
Find the zeros of 2x^2-5=8
The zeros of 2x^2-5=8 are x=sqrt(13/2),x=-sqrt(13/2)