What are the solutions to the equation 6x^2-12x+390=0 ?

The solutions to the equation 6x^2-12x+390=0 are x=1+8i,x=1-8i

Find the zeros of 6x^2-12x+390=0

The zeros of 6x^2-12x+390=0 are x=1+8i,x=1-8i

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6 x^{2} - 12 x + 390 = 0

x = 1 + 8 i, x = 1 - 8 i

Solution steps

6 x^{2} - 12 x + 390 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 6 \cdot 390}{2 \cdot 6}

Simplify

(- 12)^{2} - 4 \cdot 6 \cdot 390 : 96 i

x_{1, 2} = \frac{- ( - 12 ) \pm 96 i}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 96 i}{2 \cdot 6}, x_{2} = \frac{- ( - 12 ) - 96 i}{2 \cdot 6}

x = \frac{- ( - 12 ) + 96 i}{2 \cdot 6} : 1 + 8 i

x = \frac{- ( - 12 ) - 96 i}{2 \cdot 6} : 1 - 8 i

The solutions to the quadratic equation are:

x = 1 + 8 i, x = 1 - 8 i

x, x^{2} - 12 x - 36 = 0

5 x + 2 = - 4 x^{2}

0.225375 = 0.000015 (x + 100)^{2}

x^{2} + 6 x = - 17

x^{2} + 10 x + 6

What are the solutions to the equation 6x^2-12x+390=0 ?
The solutions to the equation 6x^2-12x+390=0 are x=1+8i,x=1-8i
Find the zeros of 6x^2-12x+390=0
The zeros of 6x^2-12x+390=0 are x=1+8i,x=1-8i