What are the solutions to the equation 5x+2=-4x^2 ?

The solutions to the equation 5x+2=-4x^2 are x=-5/8-i(sqrt(7))/8 ,x=-5/8+i(sqrt(7))/8

Find the zeros of 5x+2=-4x^2

The zeros of 5x+2=-4x^2 are x=-5/8-i(sqrt(7))/8 ,x=-5/8+i(sqrt(7))/8

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5 x + 2 = - 4 x^{2}

x = - \frac{5}{8} - i \frac{7}{8}, x = - \frac{5}{8} + i \frac{7}{8}

Solution steps

5 x + 2 = - 4 x^{2}

Switch sides

- 4 x^{2} = 5 x + 2

Move

2

to the left side

- 4 x^{2} - 2 = 5 x

Move

5 x

to the left side

- 4 x^{2} - 2 - 5 x = 0

Write in the standard form

a x^{2} + b x + c = 0

- 4 x^{2} - 5 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 ( - 4 ) ( - 2 )}{2 ( - 4 )}

Simplify

(- 5)^{2} - 4 (- 4) (- 2) : 7 i

x_{1, 2} = \frac{- ( - 5 ) \pm 7 i}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 7 i}{2 ( - 4 )}, x_{2} = \frac{- ( - 5 ) - 7 i}{2 ( - 4 )}

x = \frac{- ( - 5 ) + 7 i}{2 ( - 4 )} : - \frac{5}{8} - i \frac{7}{8}

x = \frac{- ( - 5 ) - 7 i}{2 ( - 4 )} : - \frac{5}{8} + i \frac{7}{8}

The solutions to the quadratic equation are:

x = - \frac{5}{8} - i \frac{7}{8}, x = - \frac{5}{8} + i \frac{7}{8}

0.225375 = 0.000015 (x + 100)^{2}

x^{2} + 6 x = - 17

x^{2} + 10 x + 6

y^{2} - 6 y = 16

3 x - 4 x^{2} = 8

What are the solutions to the equation 5x+2=-4x^2 ?
The solutions to the equation 5x+2=-4x^2 are x=-5/8-i(sqrt(7))/8 ,x=-5/8+i(sqrt(7))/8
Find the zeros of 5x+2=-4x^2
The zeros of 5x+2=-4x^2 are x=-5/8-i(sqrt(7))/8 ,x=-5/8+i(sqrt(7))/8