What are the solutions to the equation 3x-4x^2=8 ?

The solutions to the equation 3x-4x^2=8 are x= 3/8-i(sqrt(119))/8 ,x= 3/8+i(sqrt(119))/8

Find the zeros of 3x-4x^2=8

The zeros of 3x-4x^2=8 are x= 3/8-i(sqrt(119))/8 ,x= 3/8+i(sqrt(119))/8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x - 4 x^{2} = 8

x = \frac{3}{8} - i \frac{119}{8}, x = \frac{3}{8} + i \frac{119}{8}

Solution steps

3 x - 4 x^{2} = 8

Move

8

to the left side

3 x - 4 x^{2} - 8 = 0

Write in the standard form

a x^{2} + b x + c = 0

- 4 x^{2} + 3 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 4 ) ( - 8 )}{2 ( - 4 )}

Simplify

3^{2} - 4 (- 4) (- 8) : 119 i

x_{1, 2} = \frac{- 3 \pm 119 i}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 3 + 119 i}{2 ( - 4 )}, x_{2} = \frac{- 3 - 119 i}{2 ( - 4 )}

x = \frac{- 3 + 119 i}{2 ( - 4 )} : \frac{3}{8} - i \frac{119}{8}

x = \frac{- 3 - 119 i}{2 ( - 4 )} : \frac{3}{8} + i \frac{119}{8}

The solutions to the quadratic equation are:

x = \frac{3}{8} - i \frac{119}{8}, x = \frac{3}{8} + i \frac{119}{8}

x^{2} + 10 x + 25 = 4

\frac{1}{3} x^{2} - 8 = \frac{1}{3}

3 x^{2} = 200

169 x^{2} + 36 = 0

147 - t^{2} = 0

What are the solutions to the equation 3x-4x^2=8 ?
The solutions to the equation 3x-4x^2=8 are x= 3/8-i(sqrt(119))/8 ,x= 3/8+i(sqrt(119))/8
Find the zeros of 3x-4x^2=8
The zeros of 3x-4x^2=8 are x= 3/8-i(sqrt(119))/8 ,x= 3/8+i(sqrt(119))/8