What are the solutions to the equation 169x^2+36=0 ?

The solutions to the equation 169x^2+36=0 are x= 6/13 i,x=-6/13 i

Find the zeros of 169x^2+36=0

The zeros of 169x^2+36=0 are x= 6/13 i,x=-6/13 i

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169 x^{2} + 36 = 0

x = \frac{6}{13} i, x = - \frac{6}{13} i

Solution steps

169 x^{2} + 36 = 0

Move

36

to the right side

169 x^{2} = - 36

Divide both sides by

169

x^{2} = - \frac{36}{169}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{36}{169}, x = - - \frac{36}{169}

- \frac{36}{169} = \frac{6}{13} i

- - \frac{36}{169} = - \frac{6}{13} i

x = \frac{6}{13} i, x = - \frac{6}{13} i

147 - t^{2} = 0

6 y^{2} + 7 y + 2 = 0

4 (x - 2)^{2} - 1 = 0

(x + 8)^{2} = 9^{2}

x^{2} + 6 x = 71

What are the solutions to the equation 169x^2+36=0 ?
The solutions to the equation 169x^2+36=0 are x= 6/13 i,x=-6/13 i
Find the zeros of 169x^2+36=0
The zeros of 169x^2+36=0 are x= 6/13 i,x=-6/13 i