What are the solutions to the equation factor 20x^2-9x=20 ?

The solutions to the equation factor 20x^2-9x=20 are x=-4/5 ,x= 5/4

Find the zeros of factor 20x^2-9x=20

The zeros of factor 20x^2-9x=20 are x=-4/5 ,x= 5/4

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20 x^{2} - 9 x = 20

x = - \frac{4}{5}, x = \frac{5}{4}

Solution steps

20 x^{2} - 9 x = 20

Move

20

to the left side

20 x^{2} - 9 x - 20 = 0

Factor

20 x^{2} - 9 x - 20 : (5 x + 4) (4 x - 5)

(5 x + 4) (4 x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

5 x + 4 = 0 or 4 x - 5 = 0

Solve

5 x + 4 = 0 : x = - \frac{4}{5}

Solve

4 x - 5 = 0 : x = \frac{5}{4}

The solutions to the quadratic equation are:

x = - \frac{4}{5}, x = \frac{5}{4}

(a + 5) x^{2} + (a + 3) x + 7 - 3 a = 0

x^{2} - 120 x + 3600 = 0

x^{2} - 3 x = 2 x + 14

23 = x^{2} + 7

x, 432 = 3 x^{2}

What are the solutions to the equation factor 20x^2-9x=20 ?
The solutions to the equation factor 20x^2-9x=20 are x=-4/5 ,x= 5/4
Find the zeros of factor 20x^2-9x=20
The zeros of factor 20x^2-9x=20 are x=-4/5 ,x= 5/4