What are the solutions to the equation 2x^2+11x+19=0 ?

The solutions to the equation 2x^2+11x+19=0 are x=-11/4+i(sqrt(31))/4 ,x=-11/4-i(sqrt(31))/4

Find the zeros of 2x^2+11x+19=0

The zeros of 2x^2+11x+19=0 are x=-11/4+i(sqrt(31))/4 ,x=-11/4-i(sqrt(31))/4

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2 x^{2} + 11 x + 19 = 0

x = - \frac{11}{4} + i \frac{31}{4}, x = - \frac{11}{4} - i \frac{31}{4}

Solution steps

2 x^{2} + 11 x + 19 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 2 \cdot 19}{2 \cdot 2}

Simplify

1 1^{2} - 4 \cdot 2 \cdot 19 : 31 i

x_{1, 2} = \frac{- 11 \pm 31 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 11 + 31 i}{2 \cdot 2}, x_{2} = \frac{- 11 - 31 i}{2 \cdot 2}

x = \frac{- 11 + 31 i}{2 \cdot 2} : - \frac{11}{4} + i \frac{31}{4}

x = \frac{- 11 - 31 i}{2 \cdot 2} : - \frac{11}{4} - i \frac{31}{4}

The solutions to the quadratic equation are:

x = - \frac{11}{4} + i \frac{31}{4}, x = - \frac{11}{4} - i \frac{31}{4}

(x - 4)^{2} + (x + 2)^{2} = 25

- 54 x^{2} - 36 x + 18 = 0

x^{2} = 9 \cdot 10

4 x^{2} + 3 = 13 x

(x - 1)^{2} = 7 - x

What are the solutions to the equation 2x^2+11x+19=0 ?
The solutions to the equation 2x^2+11x+19=0 are x=-11/4+i(sqrt(31))/4 ,x=-11/4-i(sqrt(31))/4
Find the zeros of 2x^2+11x+19=0
The zeros of 2x^2+11x+19=0 are x=-11/4+i(sqrt(31))/4 ,x=-11/4-i(sqrt(31))/4