What are the solutions to the equation -54x^2-36x+18=0 ?

The solutions to the equation -54x^2-36x+18=0 are x=-1,x= 1/3

Find the zeros of -54x^2-36x+18=0

The zeros of -54x^2-36x+18=0 are x=-1,x= 1/3

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- 54 x^{2} - 36 x + 18 = 0

x = - 1, x = \frac{1}{3}

Solution steps

- 54 x^{2} - 36 x + 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 36 ) \pm ( - 36 ) ^{2} - 4 ( - 54 ) \cdot 18}{2 ( - 54 )}

(- 36)^{2} - 4 (- 54) \cdot 18 = 72

x_{1, 2} = \frac{- ( - 36 ) \pm 72}{2 ( - 54 )}

Separate the solutions

x_{1} = \frac{- ( - 36 ) + 72}{2 ( - 54 )}, x_{2} = \frac{- ( - 36 ) - 72}{2 ( - 54 )}

x = \frac{- ( - 36 ) + 72}{2 ( - 54 )} : - 1

x = \frac{- ( - 36 ) - 72}{2 ( - 54 )} : \frac{1}{3}

The solutions to the quadratic equation are:

x = - 1, x = \frac{1}{3}

x^{2} = 9 \cdot 10

4 x^{2} + 3 = 13 x

(x - 1)^{2} = 7 - x

2 w^{2} + 3 w - 1 = 0

x^{2} - 0.9 x + 0.2 = 0

What are the solutions to the equation -54x^2-36x+18=0 ?
The solutions to the equation -54x^2-36x+18=0 are x=-1,x= 1/3
Find the zeros of -54x^2-36x+18=0
The zeros of -54x^2-36x+18=0 are x=-1,x= 1/3