What are the solutions to the equation x=2x-x^2 ?

The solutions to the equation x=2x-x^2 are x=0,x=1

Find the zeros of x=2x-x^2

The zeros of x=2x-x^2 are x=0,x=1

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x = 2 x - x^{2}

x = 0, x = 1

Solution steps

x = 2 x - x^{2}

Switch sides

2 x - x^{2} = x

Move

x

to the left side

- x^{2} + x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

1^{2} - 4 (- 1) \cdot 0 = 1

x_{1, 2} = \frac{- 1 \pm 1}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 1 + 1}{2 ( - 1 )}, x_{2} = \frac{- 1 - 1}{2 ( - 1 )}

x = \frac{- 1 + 1}{2 ( - 1 )} : 0

x = \frac{- 1 - 1}{2 ( - 1 )} : 1

The solutions to the quadratic equation are:

x = 0, x = 1

2 x^{2} - 8 x + 12

2 x^{2} - 8 x + 17

4 x^{2} + 1 = 9

3 x (2 x - 5) = 3

2 s^{2} - 98 = 0

What are the solutions to the equation x=2x-x^2 ?
The solutions to the equation x=2x-x^2 are x=0,x=1
Find the zeros of x=2x-x^2
The zeros of x=2x-x^2 are x=0,x=1