What are the solutions to the equation 3x^2-4=5x ?

The solutions to the equation 3x^2-4=5x are x=(5+sqrt(73))/6 ,x=(5-sqrt(73))/6

Find the zeros of 3x^2-4=5x

The zeros of 3x^2-4=5x are x=(5+sqrt(73))/6 ,x=(5-sqrt(73))/6

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3 x^{2} - 4 = 5 x

x = \frac{5 + 73}{6}, x = \frac{5 - 73}{6}

Solution steps

3 x^{2} - 4 = 5 x

Move

5 x

to the left side

3 x^{2} - 4 - 5 x = 0

Write in the standard form

a x^{2} + b x + c = 0

3 x^{2} - 5 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 3 ( - 4 )}{2 \cdot 3}

(- 5)^{2} - 4 \cdot 3 (- 4) = 73

x_{1, 2} = \frac{- ( - 5 ) \pm 73}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 73}{2 \cdot 3}, x_{2} = \frac{- ( - 5 ) - 73}{2 \cdot 3}

x = \frac{- ( - 5 ) + 73}{2 \cdot 3} : \frac{5 + 73}{6}

x = \frac{- ( - 5 ) - 73}{2 \cdot 3} : \frac{5 - 73}{6}

The solutions to the quadratic equation are:

x = \frac{5 + 73}{6}, x = \frac{5 - 73}{6}

x^{2} - 5 = 13 - x^{2}

x, x^{2} + y^{2} - 10 x + 9 = 0

25 x^{2} - 10 x = 0

x (2 x - 7) = 4 (x - 3)

x^{2} - 2 x - 240 = 0

What are the solutions to the equation 3x^2-4=5x ?
The solutions to the equation 3x^2-4=5x are x=(5+sqrt(73))/6 ,x=(5-sqrt(73))/6
Find the zeros of 3x^2-4=5x
The zeros of 3x^2-4=5x are x=(5+sqrt(73))/6 ,x=(5-sqrt(73))/6