What are the solutions to the equation solvefor a,x=a^2+b^2+c^3 ?

The solutions to the equation solvefor a,x=a^2+b^2+c^3 are a=sqrt(x-b^2-c^3),a=-sqrt(x-b^2-c^3)

Find the zeros of solvefor a,x=a^2+b^2+c^3

The zeros of solvefor a,x=a^2+b^2+c^3 are a=sqrt(x-b^2-c^3),a=-sqrt(x-b^2-c^3)

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solve for

a, x = a^{2} + b^{2} + c^{3}

a = x - b^{2} - c^{3}, a = - x - b^{2} - c^{3}

Solution steps

x = a^{2} + b^{2} + c^{3}

Switch sides

a^{2} + b^{2} + c^{3} = x

Move

b^{2}

to the right side

a^{2} + c^{3} = x - b^{2}

Move

c^{3}

to the right side

a^{2} = x - b^{2} - c^{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

a = x - b^{2} - c^{3}, a = - x - b^{2} - c^{3}

x^{2} - 3 x = 7 x^{2} + 5 x

2 x (x - 5) = - 3 x - 3

(x - 6) (x + 2) + x^{2} + 4 = (x - 4) (x - 1)

x^{2} - 8 x + 12 = 0

x^{2} - 13 x = 30

What are the solutions to the equation solvefor a,x=a^2+b^2+c^3 ?
The solutions to the equation solvefor a,x=a^2+b^2+c^3 are a=sqrt(x-b^2-c^3),a=-sqrt(x-b^2-c^3)
Find the zeros of solvefor a,x=a^2+b^2+c^3
The zeros of solvefor a,x=a^2+b^2+c^3 are a=sqrt(x-b^2-c^3),a=-sqrt(x-b^2-c^3)