What are the solutions to the equation 6x^2+13x+7=0 ?

The solutions to the equation 6x^2+13x+7=0 are x=-1,x=-7/6

Find the zeros of 6x^2+13x+7=0

The zeros of 6x^2+13x+7=0 are x=-1,x=-7/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

6 x^{2} + 13 x + 7 = 0

x = - 1, x = - \frac{7}{6}

Solution steps

6 x^{2} + 13 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 6 \cdot 7}{2 \cdot 6}

1 3^{2} - 4 \cdot 6 \cdot 7 = 1

x_{1, 2} = \frac{- 13 \pm 1}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 13 + 1}{2 \cdot 6}, x_{2} = \frac{- 13 - 1}{2 \cdot 6}

x = \frac{- 13 + 1}{2 \cdot 6} : - 1

x = \frac{- 13 - 1}{2 \cdot 6} : - \frac{7}{6}

The solutions to the quadratic equation are:

x = - 1, x = - \frac{7}{6}

(\frac{x ^{2}}{4})^{2}

∣ 7 x - 2 ∣ \geq 5

t^{2} = 4

\frac{2}{5} x - x + \frac{5}{10} = 3 x - \frac{25}{2}

0^{2} - 3

What are the solutions to the equation 6x^2+13x+7=0 ?
The solutions to the equation 6x^2+13x+7=0 are x=-1,x=-7/6
Find the zeros of 6x^2+13x+7=0
The zeros of 6x^2+13x+7=0 are x=-1,x=-7/6