What are the solutions to the equation x(x-10)+24=0 ?

The solutions to the equation x(x-10)+24=0 are x=6,x=4

Find the zeros of x(x-10)+24=0

The zeros of x(x-10)+24=0 are x=6,x=4

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x (x - 10) + 24 = 0

x = 6, x = 4

Solution steps

x (x - 10) + 24 = 0

Expand

x (x - 10) + 24 : x^{2} - 10 x + 24

x^{2} - 10 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 24}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 24 = 2

x_{1, 2} = \frac{- ( - 10 ) \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 2}{2 \cdot 1}

x = \frac{- ( - 10 ) + 2}{2 \cdot 1} : 6

x = \frac{- ( - 10 ) - 2}{2 \cdot 1} : 4

The solutions to the quadratic equation are:

x = 6, x = 4

16.1 t^{2} + 200 t - 200 = 0

x^{2} - 19 x + 102 = - x - 6

5 x^{2} + 5 x - 5 = 0

b^{2} - 3 b - 28 = 0

28 = x^{2}

What are the solutions to the equation x(x-10)+24=0 ?
The solutions to the equation x(x-10)+24=0 are x=6,x=4
Find the zeros of x(x-10)+24=0
The zeros of x(x-10)+24=0 are x=6,x=4