What are the solutions to the equation x^2-19x+102=-x-6 ?

The solutions to the equation x^2-19x+102=-x-6 are x=9+3sqrt(3)i,x=9-3sqrt(3)i

Find the zeros of x^2-19x+102=-x-6

The zeros of x^2-19x+102=-x-6 are x=9+3sqrt(3)i,x=9-3sqrt(3)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 19 x + 102 = - x - 6

x = 9 + 33 i, x = 9 - 33 i

Solution steps

x^{2} - 19 x + 102 = - x - 6

Move

6

to the left side

x^{2} - 19 x + 108 = - x

Move

x

to the left side

x^{2} - 18 x + 108 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 1 \cdot 108}{2 \cdot 1}

Simplify

(- 18)^{2} - 4 \cdot 1 \cdot 108 : 63 i

x_{1, 2} = \frac{- ( - 18 ) \pm 6 3 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 6 3 i}{2 \cdot 1}, x_{2} = \frac{- ( - 18 ) - 6 3 i}{2 \cdot 1}

x = \frac{- ( - 18 ) + 6 3 i}{2 \cdot 1} : 9 + 33 i

x = \frac{- ( - 18 ) - 6 3 i}{2 \cdot 1} : 9 - 33 i

The solutions to the quadratic equation are:

x = 9 + 33 i, x = 9 - 33 i

5 x^{2} + 5 x - 5 = 0

b^{2} - 3 b - 28 = 0

28 = x^{2}

m = n - \frac{a x ^{2}}{2}

x^{2} - 12 x - 62 = 0

What are the solutions to the equation x^2-19x+102=-x-6 ?
The solutions to the equation x^2-19x+102=-x-6 are x=9+3sqrt(3)i,x=9-3sqrt(3)i
Find the zeros of x^2-19x+102=-x-6
The zeros of x^2-19x+102=-x-6 are x=9+3sqrt(3)i,x=9-3sqrt(3)i