What are the solutions to the equation t^2-8t+14=0 ?

The solutions to the equation t^2-8t+14=0 are t=4+sqrt(2),t=4-sqrt(2)

Find the zeros of t^2-8t+14=0

The zeros of t^2-8t+14=0 are t=4+sqrt(2),t=4-sqrt(2)

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t^{2} - 8 t + 14 = 0

t = 4 + 2, t = 4 - 2

Solution steps

t^{2} - 8 t + 14 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 14}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 14 = 22

t_{1, 2} = \frac{- ( - 8 ) \pm 2 2}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- ( - 8 ) + 2 2}{2 \cdot 1}, t_{2} = \frac{- ( - 8 ) - 2 2}{2 \cdot 1}

t = \frac{- ( - 8 ) + 2 2}{2 \cdot 1} : 4 + 2

t = \frac{- ( - 8 ) - 2 2}{2 \cdot 1} : 4 - 2

The solutions to the quadratic equation are:

t = 4 + 2, t = 4 - 2

x^{2} - 18 x + 81 = 12

- x^{2} - 3 x + 9 = - 9 + 6 x - 2 x^{2}

x^{2} - (k - 3) x - 6 = 0

x, y^{2} = 4 x^{2} + 9 z^{2}

- 100 = - 4.9 t^{2}

What are the solutions to the equation t^2-8t+14=0 ?
The solutions to the equation t^2-8t+14=0 are t=4+sqrt(2),t=4-sqrt(2)
Find the zeros of t^2-8t+14=0
The zeros of t^2-8t+14=0 are t=4+sqrt(2),t=4-sqrt(2)