What are the solutions to the equation x^2-11x+41=19 ?

The solutions to the equation x^2-11x+41=19 are x=(11+sqrt(33))/2 ,x=(11-sqrt(33))/2

Find the zeros of x^2-11x+41=19

The zeros of x^2-11x+41=19 are x=(11+sqrt(33))/2 ,x=(11-sqrt(33))/2

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x^{2} - 11 x + 41 = 19

x = \frac{11 + 33}{2}, x = \frac{11 - 33}{2}

Solution steps

x^{2} - 11 x + 41 = 19

Move

19

to the left side

x^{2} - 11 x + 22 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 1 \cdot 22}{2 \cdot 1}

(- 11)^{2} - 4 \cdot 1 \cdot 22 = 33

x_{1, 2} = \frac{- ( - 11 ) \pm 33}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 33}{2 \cdot 1}, x_{2} = \frac{- ( - 11 ) - 33}{2 \cdot 1}

x = \frac{- ( - 11 ) + 33}{2 \cdot 1} : \frac{11 + 33}{2}

x = \frac{- ( - 11 ) - 33}{2 \cdot 1} : \frac{11 - 33}{2}

The solutions to the quadratic equation are:

x = \frac{11 + 33}{2}, x = \frac{11 - 33}{2}

4 x^{2} - 3 (5 x - 1) = 0

- 0.1 x^{2} + 14 x + 3 = 1000

x (x - 5) = 4 x

16 x^{2} + 22 = 0

x^{2} + a x - b x = ab

What are the solutions to the equation x^2-11x+41=19 ?
The solutions to the equation x^2-11x+41=19 are x=(11+sqrt(33))/2 ,x=(11-sqrt(33))/2
Find the zeros of x^2-11x+41=19
The zeros of x^2-11x+41=19 are x=(11+sqrt(33))/2 ,x=(11-sqrt(33))/2