What are the solutions to the equation 17x^2+719x=0 ?

The solutions to the equation 17x^2+719x=0 are x=0,x=-719/17

Find the zeros of 17x^2+719x=0

The zeros of 17x^2+719x=0 are x=0,x=-719/17

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17 x^{2} + 719 x = 0

x = 0, x = - \frac{719}{17}

Decimal Notation

x = 0, x = - 42.29411 \dots

Solution steps

17 x^{2} + 719 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 719 \pm 71 9 ^{2} - 4 \cdot 17 \cdot 0}{2 \cdot 17}

71 9^{2} - 4 \cdot 17 \cdot 0 = 719

x_{1, 2} = \frac{- 719 \pm 719}{2 \cdot 17}

Separate the solutions

x_{1} = \frac{- 719 + 719}{2 \cdot 17}, x_{2} = \frac{- 719 - 719}{2 \cdot 17}

x = \frac{- 719 + 719}{2 \cdot 17} : 0

x = \frac{- 719 - 719}{2 \cdot 17} : - \frac{719}{17}

The solutions to the quadratic equation are:

x = 0, x = - \frac{719}{17}

y, x = y^{2} - 1

6 n^{2} + 4 n - 1 = 0

k^{2} - 2 k - 3 = 0

6 x^{2} - 12 x + 1476 = 0

x, x + 2 x^{2} - 4 = - 7 x + 6

What are the solutions to the equation 17x^2+719x=0 ?
The solutions to the equation 17x^2+719x=0 are x=0,x=-719/17
Find the zeros of 17x^2+719x=0
The zeros of 17x^2+719x=0 are x=0,x=-719/17