What are the solutions to the equation 8x^2+13x+4=3x^2 ?

The solutions to the equation 8x^2+13x+4=3x^2 are x=(-13+sqrt(89))/(10),x=(-13-sqrt(89))/(10)

Find the zeros of 8x^2+13x+4=3x^2

The zeros of 8x^2+13x+4=3x^2 are x=(-13+sqrt(89))/(10),x=(-13-sqrt(89))/(10)

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8 x^{2} + 13 x + 4 = 3 x^{2}

x = \frac{- 13 + 89}{10}, x = \frac{- 13 - 89}{10}

Solution steps

8 x^{2} + 13 x + 4 = 3 x^{2}

Move

3 x^{2}

to the left side

5 x^{2} + 13 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 5 \cdot 4}{2 \cdot 5}

1 3^{2} - 4 \cdot 5 \cdot 4 = 89

x_{1, 2} = \frac{- 13 \pm 89}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 13 + 89}{2 \cdot 5}, x_{2} = \frac{- 13 - 89}{2 \cdot 5}

x = \frac{- 13 + 89}{2 \cdot 5} : \frac{- 13 + 89}{10}

x = \frac{- 13 - 89}{2 \cdot 5} : \frac{- 13 - 89}{10}

The solutions to the quadratic equation are:

x = \frac{- 13 + 89}{10}, x = \frac{- 13 - 89}{10}

3 c^{2} + c - 11 = - 4

x (5 x + 1.5) - 2.6 = 1.6 x (2.5 x + 0.5)

- 5 x^{2} - 10 x = - 315

\frac{z ( z + 1 )}{2} = 21

a^{2} + 7 a + 6 = 0

What are the solutions to the equation 8x^2+13x+4=3x^2 ?
The solutions to the equation 8x^2+13x+4=3x^2 are x=(-13+sqrt(89))/(10),x=(-13-sqrt(89))/(10)
Find the zeros of 8x^2+13x+4=3x^2
The zeros of 8x^2+13x+4=3x^2 are x=(-13+sqrt(89))/(10),x=(-13-sqrt(89))/(10)