What are the solutions to the equation 64(x-1)^2=289 ?

The solutions to the equation 64(x-1)^2=289 are x= 25/8 ,x=-9/8

Find the zeros of 64(x-1)^2=289

The zeros of 64(x-1)^2=289 are x= 25/8 ,x=-9/8

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64 (x - 1)^{2} = 289

x = \frac{25}{8}, x = - \frac{9}{8}

Solution steps

64 (x - 1)^{2} = 289

Divide both sides by

64

(x - 1)^{2} = \frac{289}{64}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 1 = \frac{289}{64} : x = \frac{25}{8}

Solve

x - 1 = - \frac{289}{64} : x = - \frac{9}{8}

The solutions to the quadratic equation are:

x = \frac{25}{8}, x = - \frac{9}{8}

\frac{9 x ^{2} - 25}{4} = 0

z^{2} + z - 3 = 0

2 (y^{2} + 3) = 11 - 13 y

6 (1 - x) + 2 = 3 x^{2} - 17

d^{2} - 18 = 0

What are the solutions to the equation 64(x-1)^2=289 ?
The solutions to the equation 64(x-1)^2=289 are x= 25/8 ,x=-9/8
Find the zeros of 64(x-1)^2=289
The zeros of 64(x-1)^2=289 are x= 25/8 ,x=-9/8