What are the solutions to the equation 5x^2-38x-16=0 ?

The solutions to the equation 5x^2-38x-16=0 are x=8,x=-2/5

Find the zeros of 5x^2-38x-16=0

The zeros of 5x^2-38x-16=0 are x=8,x=-2/5

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5 x^{2} - 38 x - 16 = 0

x = 8, x = - \frac{2}{5}

Decimal Notation

x = 8, x = - 0.4

Solution steps

5 x^{2} - 38 x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 38 ) \pm ( - 38 ) ^{2} - 4 \cdot 5 ( - 16 )}{2 \cdot 5}

(- 38)^{2} - 4 \cdot 5 (- 16) = 42

x_{1, 2} = \frac{- ( - 38 ) \pm 42}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 38 ) + 42}{2 \cdot 5}, x_{2} = \frac{- ( - 38 ) - 42}{2 \cdot 5}

x = \frac{- ( - 38 ) + 42}{2 \cdot 5} : 8

x = \frac{- ( - 38 ) - 42}{2 \cdot 5} : - \frac{2}{5}

The solutions to the quadratic equation are:

x = 8, x = - \frac{2}{5}

n - 5 n + 12 = 3 n^{2}

x^{2} + 8 x - 9 = 0

- 6 x^{2} + 7 x = 7 x - 4

- z^{2} - 7 z - 4 = - 2 z^{2}

x, f (x - 2) = - 3 x^{2} - 1

What are the solutions to the equation 5x^2-38x-16=0 ?
The solutions to the equation 5x^2-38x-16=0 are x=8,x=-2/5
Find the zeros of 5x^2-38x-16=0
The zeros of 5x^2-38x-16=0 are x=8,x=-2/5