What are the solutions to the equation -6x^2+7x=7x-4 ?

The solutions to the equation -6x^2+7x=7x-4 are x=sqrt(2/3),x=-sqrt(2/3)

Find the zeros of -6x^2+7x=7x-4

The zeros of -6x^2+7x=7x-4 are x=sqrt(2/3),x=-sqrt(2/3)

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- 6 x^{2} + 7 x = 7 x - 4

x = \frac{2}{3}, x = - \frac{2}{3}

Solution steps

- 6 x^{2} + 7 x = 7 x - 4

Move

7 x

to the left side

- 6 x^{2} = - 4

Divide both sides by

- 6

x^{2} = \frac{2}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{2}{3}, x = - \frac{2}{3}

- z^{2} - 7 z - 4 = - 2 z^{2}

x, f (x - 2) = - 3 x^{2} - 1

x, y (x^{2} - 1) = 2

6 - 2 x^{2} = 6 x

x^{2} + 40 = - 14 x

What are the solutions to the equation -6x^2+7x=7x-4 ?
The solutions to the equation -6x^2+7x=7x-4 are x=sqrt(2/3),x=-sqrt(2/3)
Find the zeros of -6x^2+7x=7x-4
The zeros of -6x^2+7x=7x-4 are x=sqrt(2/3),x=-sqrt(2/3)