What are the solutions to the equation x^2-9x=7 ?

The solutions to the equation x^2-9x=7 are x=(9+sqrt(109))/2 ,x=(9-sqrt(109))/2

Find the zeros of x^2-9x=7

The zeros of x^2-9x=7 are x=(9+sqrt(109))/2 ,x=(9-sqrt(109))/2

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x^{2} - 9 x = 7

x = \frac{9 + 109}{2}, x = \frac{9 - 109}{2}

Decimal Notation

x = 9.72015 \dots, x = - 0.72015 \dots

Solution steps

x^{2} - 9 x = 7

Move

7

to the left side

x^{2} - 9 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot ( - 7 )}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot (- 7) = 109

x_{1, 2} = \frac{- ( - 9 ) \pm 109}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 109}{2 \cdot 1}, x_{2} = \frac{- ( - 9 ) - 109}{2 \cdot 1}

x = \frac{- ( - 9 ) + 109}{2 \cdot 1} : \frac{9 + 109}{2}

x = \frac{- ( - 9 ) - 109}{2 \cdot 1} : \frac{9 - 109}{2}

The solutions to the quadratic equation are:

x = \frac{9 + 109}{2}, x = \frac{9 - 109}{2}

7 x^{2} - 78 x = 0

x^{2} - 3 = 9

(2 a - 1) x^{2} + a x + 5 = 0

(\frac{1 + x}{4})^{2} = 9

2 x^{2} - 5 x - 3 = 0

What are the solutions to the equation x^2-9x=7 ?
The solutions to the equation x^2-9x=7 are x=(9+sqrt(109))/2 ,x=(9-sqrt(109))/2
Find the zeros of x^2-9x=7
The zeros of x^2-9x=7 are x=(9+sqrt(109))/2 ,x=(9-sqrt(109))/2