What are the solutions to the equation ((1+x)/4)^2=9 ?

The solutions to the equation ((1+x)/4)^2=9 are x=11,x=-13

Find the zeros of ((1+x)/4)^2=9

The zeros of ((1+x)/4)^2=9 are x=11,x=-13

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(\frac{1 + x}{4})^{2} = 9

x = 11, x = - 13

Solution steps

(\frac{1 + x}{4})^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

\frac{1 + x}{4} = 9 : x = 11

Solve

\frac{1 + x}{4} = - 9 : x = - 13

The solutions to the quadratic equation are:

x = 11, x = - 13

2 x^{2} - 5 x - 3 = 0

(x + 6)^{2} - 4 (x + 6) - 12 = 0

r^{2} + 11 r + 24 = 0

2 x^{2} = - 30 x - 112

(m + 3) (m + 2) = 0

What are the solutions to the equation ((1+x)/4)^2=9 ?
The solutions to the equation ((1+x)/4)^2=9 are x=11,x=-13
Find the zeros of ((1+x)/4)^2=9
The zeros of ((1+x)/4)^2=9 are x=11,x=-13