What are the solutions to the equation (x+6)^2-4(x+6)-12=0 ?

The solutions to the equation (x+6)^2-4(x+6)-12=0 are x=0,x=-8

Find the zeros of (x+6)^2-4(x+6)-12=0

The zeros of (x+6)^2-4(x+6)-12=0 are x=0,x=-8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x + 6)^{2} - 4 (x + 6) - 12 = 0

x = 0, x = - 8

Solution steps

(x + 6)^{2} - 4 (x + 6) - 12 = 0

Expand

(x + 6)^{2} - 4 (x + 6) - 12 : x^{2} + 8 x

x^{2} + 8 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 0 = 8

x_{1, 2} = \frac{- 8 \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 8}{2 \cdot 1}, x_{2} = \frac{- 8 - 8}{2 \cdot 1}

x = \frac{- 8 + 8}{2 \cdot 1} : 0

x = \frac{- 8 - 8}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

x = 0, x = - 8

r^{2} + 11 r + 24 = 0

2 x^{2} = - 30 x - 112

(m + 3) (m + 2) = 0

(2 x + 3)^{2} - 4 x = 13 - 7 x

- 4 x^{2} + 32 x + 80 = 0

What are the solutions to the equation (x+6)^2-4(x+6)-12=0 ?
The solutions to the equation (x+6)^2-4(x+6)-12=0 are x=0,x=-8
Find the zeros of (x+6)^2-4(x+6)-12=0
The zeros of (x+6)^2-4(x+6)-12=0 are x=0,x=-8