What are the solutions to the equation (m+3)(m+2)=0 ?

The solutions to the equation (m+3)(m+2)=0 are m=-3,m=-2

Find the zeros of (m+3)(m+2)=0

The zeros of (m+3)(m+2)=0 are m=-3,m=-2

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(m + 3) (m + 2) = 0

m = - 3, m = - 2

Solution steps

(m + 3) (m + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

m + 3 = 0 or m + 2 = 0

Solve

m + 3 = 0 : m = - 3

Solve

m + 2 = 0 : m = - 2

The solutions to the quadratic equation are:

m = - 3, m = - 2

(2 x + 3)^{2} - 4 x = 13 - 7 x

- 4 x^{2} + 32 x + 80 = 0

x^{2} + 8 x = - 12 + 0

- 2 x^{2} + 5 x + 8 = 0

5 x^{2} + 29 x + 20 = 0

What are the solutions to the equation (m+3)(m+2)=0 ?
The solutions to the equation (m+3)(m+2)=0 are m=-3,m=-2
Find the zeros of (m+3)(m+2)=0
The zeros of (m+3)(m+2)=0 are m=-3,m=-2