What are the solutions to the equation (x+1)(8x+1)=18x ?

The solutions to the equation (x+1)(8x+1)=18x are x=1,x= 1/8

Find the zeros of (x+1)(8x+1)=18x

The zeros of (x+1)(8x+1)=18x are x=1,x= 1/8

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(x + 1) (8 x + 1) = 18 x

x = 1, x = \frac{1}{8}

Solution steps

(x + 1) (8 x + 1) = 18 x

Expand

(x + 1) (8 x + 1) : 8 x^{2} + 9 x + 1

8 x^{2} + 9 x + 1 = 18 x

Move

18 x

to the left side

8 x^{2} - 9 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 8 \cdot 1}{2 \cdot 8}

(- 9)^{2} - 4 \cdot 8 \cdot 1 = 7

x_{1, 2} = \frac{- ( - 9 ) \pm 7}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 7}{2 \cdot 8}, x_{2} = \frac{- ( - 9 ) - 7}{2 \cdot 8}

x = \frac{- ( - 9 ) + 7}{2 \cdot 8} : 1

x = \frac{- ( - 9 ) - 7}{2 \cdot 8} : \frac{1}{8}

The solutions to the quadratic equation are:

x = 1, x = \frac{1}{8}

x, x^{2} - k x - 2 = 0

81 - x^{2} = 2 x^{2}

2 (x + 5)^{2} - 6 = 0

x^{2} - (5 - 3 x) = x + 10

x^{2} - 9 x = x + 24

What are the solutions to the equation (x+1)(8x+1)=18x ?
The solutions to the equation (x+1)(8x+1)=18x are x=1,x= 1/8
Find the zeros of (x+1)(8x+1)=18x
The zeros of (x+1)(8x+1)=18x are x=1,x= 1/8