What are the solutions to the equation 2(x+5)^2-6=0 ?

The solutions to the equation 2(x+5)^2-6=0 are x=sqrt(3)-5,x=-sqrt(3)-5

Find the zeros of 2(x+5)^2-6=0

The zeros of 2(x+5)^2-6=0 are x=sqrt(3)-5,x=-sqrt(3)-5

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2 (x + 5)^{2} - 6 = 0

x = 3 - 5, x = - 3 - 5

Solution steps

2 (x + 5)^{2} - 6 = 0

Move

6

to the right side

2 (x + 5)^{2} = 6

Divide both sides by

2

(x + 5)^{2} = 3

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 5 = 3 : x = 3 - 5

Solve

x + 5 = - 3 : x = - 3 - 5

The solutions to the quadratic equation are:

x = 3 - 5, x = - 3 - 5

x^{2} - (5 - 3 x) = x + 10

x^{2} - 9 x = x + 24

2 x^{2} + 5 x = 0

8 x^{2} - 16 x - 4 = 0

(2 x - 6)^{2} - 64 = 0

What are the solutions to the equation 2(x+5)^2-6=0 ?
The solutions to the equation 2(x+5)^2-6=0 are x=sqrt(3)-5,x=-sqrt(3)-5
Find the zeros of 2(x+5)^2-6=0
The zeros of 2(x+5)^2-6=0 are x=sqrt(3)-5,x=-sqrt(3)-5