What are the solutions to the equation factor 2x^2+5x=0 ?

The solutions to the equation factor 2x^2+5x=0 are x=0,x=-5/2

Find the zeros of factor 2x^2+5x=0

The zeros of factor 2x^2+5x=0 are x=0,x=-5/2

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2 x^{2} + 5 x = 0

x = 0, x = - \frac{5}{2}

Solution steps

2 x^{2} + 5 x = 0

Factor

2 x^{2} + 5 x : x (2 x + 5)

x (2 x + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 2 x + 5 = 0

Solve

2 x + 5 = 0 : x = - \frac{5}{2}

The solutions to the quadratic equation are:

x = 0, x = - \frac{5}{2}

8 x^{2} - 16 x - 4 = 0

(2 x - 6)^{2} - 64 = 0

y, 2 x - y^{2} = 7

5 x^{2} - 18 x + 12 = 0

2 (x + 6)^{2} = 24

What are the solutions to the equation factor 2x^2+5x=0 ?
The solutions to the equation factor 2x^2+5x=0 are x=0,x=-5/2
Find the zeros of factor 2x^2+5x=0
The zeros of factor 2x^2+5x=0 are x=0,x=-5/2