What are the solutions to the equation 2p^2+13p+17=0 ?

The solutions to the equation 2p^2+13p+17=0 are p=(-13+sqrt(33))/4 ,p=(-13-sqrt(33))/4

Find the zeros of 2p^2+13p+17=0

The zeros of 2p^2+13p+17=0 are p=(-13+sqrt(33))/4 ,p=(-13-sqrt(33))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 p^{2} + 13 p + 17 = 0

p = \frac{- 13 + 33}{4}, p = \frac{- 13 - 33}{4}

Solution steps

2 p^{2} + 13 p + 17 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 2 \cdot 17}{2 \cdot 2}

1 3^{2} - 4 \cdot 2 \cdot 17 = 33

p_{1, 2} = \frac{- 13 \pm 33}{2 \cdot 2}

Separate the solutions

p_{1} = \frac{- 13 + 33}{2 \cdot 2}, p_{2} = \frac{- 13 - 33}{2 \cdot 2}

p = \frac{- 13 + 33}{2 \cdot 2} : \frac{- 13 + 33}{4}

p = \frac{- 13 - 33}{2 \cdot 2} : \frac{- 13 - 33}{4}

The solutions to the quadratic equation are:

p = \frac{- 13 + 33}{4}, p = \frac{- 13 - 33}{4}

x^{2} + 16 x = - 59

3 (4 b^{2} - 7) = - 2 b - 8

4 x^{2} + 20 x

x - 7 = (x - 1)^{2}

x, 25 x^{2} + k x + 4 = 0

What are the solutions to the equation 2p^2+13p+17=0 ?
The solutions to the equation 2p^2+13p+17=0 are p=(-13+sqrt(33))/4 ,p=(-13-sqrt(33))/4
Find the zeros of 2p^2+13p+17=0
The zeros of 2p^2+13p+17=0 are p=(-13+sqrt(33))/4 ,p=(-13-sqrt(33))/4