What are the solutions to the equation 3q^2-147=0 ?

The solutions to the equation 3q^2-147=0 are q=7,q=-7

Find the zeros of 3q^2-147=0

The zeros of 3q^2-147=0 are q=7,q=-7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 q^{2} - 147 = 0

q = 7, q = - 7

Solution steps

3 q^{2} - 147 = 0

Move

147

to the right side

3 q^{2} = 147

Divide both sides by

3

q^{2} = 49

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

q = 49, q = - 49

49 = 7

- 49 = - 7

q = 7, q = - 7

2 x^{2} - 6 x + 5 = 0

(x + 3)^{2} - 169 = 0

- 3 x^{2} - 2 x - 1 = 0

x^{2} + a^{2} - b x + ab = 0

3 + 5 d = 4 d^{2}

What are the solutions to the equation 3q^2-147=0 ?
The solutions to the equation 3q^2-147=0 are q=7,q=-7
Find the zeros of 3q^2-147=0
The zeros of 3q^2-147=0 are q=7,q=-7