What are the solutions to the equation 4-2x+3x^2=0 ?

The solutions to the equation 4-2x+3x^2=0 are x= 1/3+i(sqrt(11))/3 ,x= 1/3-i(sqrt(11))/3

Find the zeros of 4-2x+3x^2=0

The zeros of 4-2x+3x^2=0 are x= 1/3+i(sqrt(11))/3 ,x= 1/3-i(sqrt(11))/3

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4 - 2 x + 3 x^{2} = 0

x = \frac{1}{3} + i \frac{11}{3}, x = \frac{1}{3} - i \frac{11}{3}

Solution steps

4 - 2 x + 3 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

3 x^{2} - 2 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 3 \cdot 4}{2 \cdot 3}

Simplify

(- 2)^{2} - 4 \cdot 3 \cdot 4 : 211 i

x_{1, 2} = \frac{- ( - 2 ) \pm 2 11 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 11 i}{2 \cdot 3}, x_{2} = \frac{- ( - 2 ) - 2 11 i}{2 \cdot 3}

x = \frac{- ( - 2 ) + 2 11 i}{2 \cdot 3} : \frac{1}{3} + i \frac{11}{3}

x = \frac{- ( - 2 ) - 2 11 i}{2 \cdot 3} : \frac{1}{3} - i \frac{11}{3}

The solutions to the quadratic equation are:

x = \frac{1}{3} + i \frac{11}{3}, x = \frac{1}{3} - i \frac{11}{3}

x, y = \frac{x ^{2}}{4}

(x - 4)^{2} + 3 (x + 1) (x - 2) = 8

x, f (x + 2) = x^{2} - x

r^{2} - 144 = 0

4 x^{2} + 26 x + 30 = 0

What are the solutions to the equation 4-2x+3x^2=0 ?
The solutions to the equation 4-2x+3x^2=0 are x= 1/3+i(sqrt(11))/3 ,x= 1/3-i(sqrt(11))/3
Find the zeros of 4-2x+3x^2=0
The zeros of 4-2x+3x^2=0 are x= 1/3+i(sqrt(11))/3 ,x= 1/3-i(sqrt(11))/3